SOLUTION: Find the mean and standard deviation for a binomial distribution with 912 trials and a probability of success of 0.21 and enter the answers below. Round each value to two decimal p

Algebra ->  Probability-and-statistics -> SOLUTION: Find the mean and standard deviation for a binomial distribution with 912 trials and a probability of success of 0.21 and enter the answers below. Round each value to two decimal p      Log On


   

Question 1149472: Find the mean and standard deviation for a binomial distribution with 912 trials and a probability of success of 0.21 and enter the answers below. Round each value to two decimal places.
Mean:
Standard deviation:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
mean is np=912*0.21=191.52
variance is np(1-p)=912.52*0.79=151.3008
sd is sqrt (V)=12.30