Question 1149312: You have 10 milliliters of a drink that contains 71% water. How many milliliters of a drink containing 19% water needs to be added in order to have a final drink that is 32% water?
Found 3 solutions by Boreal, josgarithmetic, ikleyn:
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! adding x ml 19% water
start with 7.10 ml pure water (0.71*10)and add 0.19x ml, which is 7.10 +0.19x ml
final is (10+x)ml*0.32=3.2 ml+0.32x ml
Those two are equal, so 3.2+0.32x=7.10+0.19x
0.13x=3.9
x=30 ml
check started with 7.10 ml pure water and ended with 7.1 +5.7 (30*.19)=12.8 ml
also have 40 ml of .32 pure water which is also 12.8 ml
Answer by josgarithmetic(39620)  (Show Source):
Answer by ikleyn(52803)  (Show Source):
You can put this solution on YOUR website! .
When I see such posts from @josgarithmetic, I become really sad and angry.
The educational value of such posts is 0 (zero, ZERO).
Moreover, posting such a nonsense, he actually blocks the posts from other tutors (from me, for example),
from which the reader / (the visitor) could learn something useful.
It is why I say that real contribution of @josgarithmetic is, actually, NEGATIVE at this forum.
Dear visitors, you will continue to get such GIBBERISH from him until YOU APPLAUD him.
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