SOLUTION: the admission fee at the fair is $3 for children and $6 for adults. on a certain day, 2000 people enter the fair and $8100 is collected. how many children and how many adults atten

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: the admission fee at the fair is $3 for children and $6 for adults. on a certain day, 2000 people enter the fair and $8100 is collected. how many children and how many adults atten      Log On


   

Question 1149253: the admission fee at the fair is $3 for children and $6 for adults. on a certain day, 2000 people enter the fair and $8100 is collected. how many children and how many adults attended
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.

Let  "x"  be the number of children;  then the number of adults is  (2000-x).


The money equation is


    3x + 6*(2000-x) = 8100.


From the equation, express "x" and  calculate


    x = %288100-6%2A2000%29%2F%283+-+6%29 = 1300.


ANSWER.  1300 children  and  200-1300 = 700 adults.


CHECK.   1300*3 + 700*6 = 8100 dollars.   ! Correct !

Solved.

-------------------

It is a standard tickets problem.

There are different methods of solving such problems.
Read the lessons
    - Using systems of equations to solve problems on tickets
    - Three methods for solving standard (typical) problems on tickets
in this site.

From these lessons,  learn on how to solve such problems once and for all.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Systems of two linear equations in two unknowns".

Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.