SOLUTION: hey, i couldn't find the answer of this equation, could u please solve it for me. okay. A radius of a circle has end points at O(-1,3) and R(2,2). Find two possible end points fo

Algebra ->  Test -> SOLUTION: hey, i couldn't find the answer of this equation, could u please solve it for me. okay. A radius of a circle has end points at O(-1,3) and R(2,2). Find two possible end points fo      Log On


   



Question 114912: hey,
i couldn't find the answer of this equation, could u please solve it for me.
okay. A radius of a circle has end points at O(-1,3) and R(2,2). Find two possible end points for the diameter that contains the radius.
And thank you,
i will be waiting for the answer.

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
a diameter is twice the radius, actually two radii end-to-end

the two end points given in the queation could be end points of diameters, depending on which end another radius is added

going from O to R, adds 3 to the x value and -1 to the y; so the other end of a diameter starting at O would be (5,1)

similarly, R to O is -3 in x an 1 in y; the other end of a diameter starting at R would be (-4,4)