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Question 1148948: Hi, I need help solving this word problem. Its seems we need to find two answers but not sure how to.
Word Problem; "Two buses leave towns 610 km apart at the same time and travel toward each other. One bus travels 5 km per hour faster than the other. If they meet in 4 hours, what is the rate of each bus? (Label which speed is for which bus"
Thank you
Answer by ikleyn(52786) (Show Source):
You can put this solution on YOUR website! .
Let x be the rate of the slower bus, in kilometers per hour.
Then the rate of the other bus is (x+5) kilometers per hour, according to the condition.
In 4 hours, the slower bus traveled 4*x kilometers, while the faster bus traveled 4*(x+5) kilometers.
In 4 hours, they meet each other, which means that the sum of the traveled distances is the total distance
4x + 4*(x+5) = 610 kilometers.
Thus you get your basic equation. Now your task is to solve it.
For it, simplify the equation step by step.
4x + 4x + 20 = 610
8x = 610 - 20
8x = 590
x = 590/8 = 73.75 kilometers per hour.
Thus you found the rate of the slower bus.
Then the rate of the faster bus is 73.75 + 5 = 78.75 km/h.
CHECK. 4*73.75 + 4*78.75 = 610 kilometers. ! Precisely correct !
ANSWER. 73.75 km/h for the slower bus and 78.75 km/h for the faster bus.
Solved.
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See introductory lessons on Travel and Distance problems
- Travel and Distance problems
- Travel and Distance problems for two bodies moving in opposite directions
- Travel and Distance problems for two bodies moving in the same direction (catching up)
in this site.
They are written specially for you.
You will find the solutions of many similar problems there.
Read them and learn once and for all from these lessons on how to solve simple Travel and Distance problems.
Become an expert in this area.
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You did it VERY REASONABLY by dividing your original post in two SEPARATE problems.
Never submit more than one problem per post to this forum.
Those who violate this rule, work AGAINST their own interests.
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