SOLUTION: Show that the product of 6x^2-13x-5, 15x^2-16x-7, and 10x^2-39x+35 is a perfect square by showing that it is the square of another polynomial.
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-> SOLUTION: Show that the product of 6x^2-13x-5, 15x^2-16x-7, and 10x^2-39x+35 is a perfect square by showing that it is the square of another polynomial.
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Question 114879: Show that the product of 6x^2-13x-5, 15x^2-16x-7, and 10x^2-39x+35 is a perfect square by showing that it is the square of another polynomial. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Show that the product of 6x^2-13x-5, 15x^2-16x-7, and 10x^2-39x+35 is a perfect square by showing that it is the square of another polynomial.
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6x^2-13x-5 = (2x-5)(3x+1)
15x^2-16x-7= (5x-7)(3x+1)
10x^2-39x+35= (2x-5)(5x-7)
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Product = [(2x-5)(3x+1)(5x-7)]^2
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Cheers,
Stan H.
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