SOLUTION: A pilot takes a trip to visit relatives there at a speed of 100 miles per hour. On the way back home, the pilot travels at 80 miles per hour. If the round trip took nine hours, how

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: A pilot takes a trip to visit relatives there at a speed of 100 miles per hour. On the way back home, the pilot travels at 80 miles per hour. If the round trip took nine hours, how      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1148730: A pilot takes a trip to visit relatives there at a speed of 100 miles per hour. On the way back home, the pilot travels at 80 miles per hour. If the round trip took nine hours, how far did the pilot travel to visit her relatives?
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
------------------------------------------
A pilot takes a trip to visit relatives. The trip there at a speed of 100 miles per hour. On the way back home, the pilot travels at 80 miles per hour. If the round trip took nine hours, how far did the pilot travel to visit her relatives?
------------------------------------------ 

                  SPEED     TIME         DISTANCE

GOING THERE        100       d/100          d

CAME BACK           80       d/80           d

TOTAL                         9

d%2F100%2Bd%2F80=9
-
%28d%2A80%2Bd%2A100%29%2F8000=9
d%28180%2F8000%29=9
d=9%288000%2F180%29
d=9%28800%2F18%29
d=800%2F2
highlight%28d=400%29

Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!


The ratio of the two speeds is 100:80 or 5:4, and the two distances are the same. That means the ratio of the two times is 4:5.

So let the time going be 4x and the time returning be 5x. The total time was 9 hours, so

4x%2B5x+=+9
9x+=+9
x+=+1

The time going was 4x = 4 hours; the time returning was 5x = 5 hours.

So the distance each direction is 4(100) = 5(80) = 400 miles.