SOLUTION: ronald can row 24 miles in 3 hours when he rows with the current. against the same current, ronald can now only 2/3 of this distance in 4 hours. find the rate of the current (use 2
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-> SOLUTION: ronald can row 24 miles in 3 hours when he rows with the current. against the same current, ronald can now only 2/3 of this distance in 4 hours. find the rate of the current (use 2
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Question 1148620: ronald can row 24 miles in 3 hours when he rows with the current. against the same current, ronald can now only 2/3 of this distance in 4 hours. find the rate of the current (use 2 variables, thanks!) Answer by ikleyn(52809) (Show Source):
Let u be the rate of rowing in still water and v be the rate of the current.
Then the effective rate downstream is
u + v = = 8 miles per hour. (1)
while the effective rate upstream is
u - v = = 4 miles per hours. (2) (Notice 16 is 2/3 of 24 miles)
Now subtract equation (2) from equation (1).
You will get
2v = 8 - 4 = 4
v = 4/2 = 2 miles per hour.
ANSWER. The rate of the current is 2 miles per hour.
Solved using 2 variables, as it was requested.
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It is a typical and standard Upstream and Downstream round trip word problem.