SOLUTION: Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level.
95% confidence; n = 2
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95% confidence; n = 2
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Question 1148521: Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level.
95% confidence; n = 2388, x = 1672 Answer by amarjeeth123(570) (Show Source):
You can put this solution on YOUR website! We are given that x=1672 and n=2388
ph=(x/n)=(1672/2388)=0.7
Significance level=1-confidence=1-0.95=0.05
Critical z-value=z(at alpha/2)=z(0.05/2)=z(at 0.025)=1.96(from z-table)
SE=Standard error of ph=SE==0.009377
E=Critical z-value*SE=1.96*0.009377=0.01838
Margin of Error=E=0.01838
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