SOLUTION: ABC is a right angle isosceles triangle, angle BCA = 90, with BC as the base and AB as hypotenuse side AC = BC. Point M is at midpoint on hypotenuse such that BM=MA=36cm. P and Q a
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-> SOLUTION: ABC is a right angle isosceles triangle, angle BCA = 90, with BC as the base and AB as hypotenuse side AC = BC. Point M is at midpoint on hypotenuse such that BM=MA=36cm. P and Q a
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Question 1148503: ABC is a right angle isosceles triangle, angle BCA = 90, with BC as the base and AB as hypotenuse side AC = BC. Point M is at midpoint on hypotenuse such that BM=MA=36cm. P and Q are points on sides BC and AC respectively. An equilateral triangle is formed by joining MPQ. Find the area of equilateral triangle MPQ. Answer by ikleyn(52786) (Show Source):
1. Make a sketch.
2. Due to symmetry, angle BMP = angle AMQ = 60°.
3. Consider triangle BMP.
Its side BM is 36 cm; its side MP is unknown; let it be "a" cm long.
Its angle BMP is 60°; its angle MBP is 45°.
Its angle MPB = 180° - 60° - 45° = 105°.
4. Apply the sine law theorem to triangle BMP.
= . (1)
Use sin(105°) = sin(180°-105°) = sin(75°) = sin(45°+30°) = sin(45°)*cos*30°) + cos(45°)*sin(30°) = = .
Use sin(45°) = .
Then from (1) you get
a = = = . (2)
It is the final formula for the unknown side length "a".
If in addition to the final formula (2) you need its numerical value,
here it is a = 26.354 centimeters, with 3 correct decimal places after the decimal dot.
Now, if you want to find the area of the triangle MPQ, use the formula
area = = = 300.74 cm^2.