Question 1148442: a man is older than his wife by 3 years. 5 years ago the ratio of their age is 4:3, find the percentage of their age Found 2 solutions by ankor@dixie-net.com, greenestamps:Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! a man is older than his wife by 3 years.
x = man's present age
wife is 5 yrs younger therefore:
(x-5) = wife's age
:
5 years ago the ratio of their age is 4:3, =
: =
cross multiply
4(x-10) = 3(x-5)
4x - 40 = 3x - 15
4x - 3x = -15 + 40
x = 25 is the mans age
then obviously
20 = the wife's age
:
find the percentage of their age * 100 = 80% is the wife's percentage of the man's age
or = .25, man is 25% older than the wife
I don't know what you mean by "percentage of their ages", so I will ignore that....
The difference in their ages is 3 years.
When the ratio of their ages was 4:3, their ages had to be 12 and 9.
(When the ratio of their ages was 4:3, their ages were 4x and 3x; the difference is x. But we know the difference is 3; so their ages were 4x=12 and 3x=9.)
It was 5 years ago that the ratio of their ages was 4:3; that means their ages now are 12+5=17 and 9+5=14.
