SOLUTION: Suppose f(x,y,z) = 4x^2-3xz+2yz^2 find f(3,0,1)
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Question 1148180
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Suppose f(x,y,z) = 4x^2-3xz+2yz^2 find f(3,0,1)
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Alan3354(69443)
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Suppose f(x,y,z) = 4x^2-3xz+2yz^2 find f(3,0,1)
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It's substitution.
Sub 3 for x, 0 for y and 1 for z.