SOLUTION: 1:Log[log(2+log2(x+1)]=0 2:ln(x-1)+ln(2x-1)=2ln(x+1)

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Question 1148069: 1:Log[log(2+log2(x+1)]=0
2:ln(x-1)+ln(2x-1)=2ln(x+1)
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
1:Log[log(2+log2(x+1)]=0
Parentheses don't match
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2:ln(x-1)+ln(2x-1)=2ln(x+1)
ln((x-1)*(2x-1)) = ln((x+1)^2)
(x-1)*(2x-1) = (x+1)^2
2x^2 - 3x + 1 = x^2 + 2x + 1
x^2 - 5x = 0
x = 0 ********* not allowed
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x = 5