SOLUTION: The denominator of the fraction is 2 more than the numerator. If 1 is subtracted from the numerator and 2 is added to the denominator the numerator becomes half of the denominat

 

D = N + 2

NEW numerator = N-1

NEW denominator = D+2

NEW numerator = N-1 = (1/2)(D+2) 

Multiply both sides by 2:

             2(N-1) = 2(1/2)(D+2)
               2N-2 = D+2
               2N-D = 4

So we have the system of two equations in two unknowns:



YOU solve that system for the values of N and D by substitution.

Put the original numerator, the value of N, over D, the
value of the denominator.  DO NOT REDUCE THE FRACTION!!!

Edwin

Let n = the numerator;  then the denominator = (n+2).


The condition says


    n-1 = 


Multiply both sides by 2 and then simplify


    2n - 2 = ((n+2) + 2

    2n - 2 = n + 4

    2n - n = 4 + 2

     n     = 6


ANSWER.  The numerator is 6;  the denominator is 6+2 = 8.

         The fraction is   = .    ANSWER