Question 1147971: Use the given data to find the minimum sample size required to estimate the population proportion Margin of error 0.008, confidence level: 98%; p and q unknown
Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! minimum sample size(n) = N * X/(X +N -1)
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X = (z*)^2 * p * q/(margin of error)^2
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margin of error = 0.008
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confidence level = 98%, therefore z* = 2.33
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since p and q are not known, we make the following estimates p = 0.50, q = 0.50, population size(N) is 100,000
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X = (2.33)^2 * (0.50) * (0.50)/(0.008) = 169.6531
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n = 100000 * 169.6531/(169.6531 +100000 -1) = 169.3675
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minimum sample size is 170
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