SOLUTION: You have one type of candy that sells for $4.10/lb and another type of candy that sells for $8.70/lb. You would like to have 32.2 lbs of a candy mixture that sells for $4.50/lb. Ho
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: You have one type of candy that sells for $4.10/lb and another type of candy that sells for $8.70/lb. You would like to have 32.2 lbs of a candy mixture that sells for $4.50/lb. Ho
Log On
Question 1147783: You have one type of candy that sells for $4.10/lb and another type of candy that sells for $8.70/lb. You would like to have 32.2 lbs of a candy mixture that sells for $4.50/lb. How much of each candy will you need to obtain the desired mixture?
You can put this solution on YOUR website! Lbs. of $4.10 candy = a
Lbs. of $8.70 candy = b
Make two equations:
a + b = 32.2
4.10a + 8.70b = 4.50(32.2)
Simplify second equation:
a + b = 32.2
4.10a + 8.70b = 144.9
Multiply the first equation by -8.70:
-8.70a - 8.70b = -280.14
4.10a + 8.70b = 144.9
Add both equations together and solve for a:
-4.60a = -135.24
a = 29.4
Plug a = 29.4 into the original first equation and solve for b:
a + b = 32.2
29.4 + b = 32.2
b = 2.8
Lbs. of $4.10 candy = a = 29.4
Lbs. of $8.70 candy = b = 2.8
