SOLUTION: Your car radiator can hold 4 liters of fluid. Many automotive stores sell jugs of pure antifreeze, but some also sell jugs of antifreeze that have been premixed with water. Suppose

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: Your car radiator can hold 4 liters of fluid. Many automotive stores sell jugs of pure antifreeze, but some also sell jugs of antifreeze that have been premixed with water. Suppose      Log On

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Question 1147729: Your car radiator can hold 4 liters of fluid. Many automotive stores sell jugs of pure antifreeze, but some also sell jugs of antifreeze that have been premixed with water. Suppose you buy a jug of 40% antifreeze mixture as well as a jug of pure antifreeze. How many liters of each jug must you use to make enough of a 70% mixture to fill your radiator?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
M=4 liters
H=100 percent
L=40%
T=70%
v, unknown volume of the 100% liquid

Hv%2BL%28M-v%29=TM
-
Hv%2BLM-Lv=TM
Hv-Lv=TM-LM
highlight%28v=M%28T-L%29%2F%28H-L%29%29------------substitute given values and evaluate; then use for evaluating M-v.

Answer by ikleyn(52817) About Me  (Show Source):
You can put this solution on YOUR website!
.

            It is typical and standard problem on mixture.

            It intently includes many words and whole story to confuse the reader and distract his (or her) attention.

            Its shortest formulation is THIS :

              How much of pure antifreeze and how much of 40% antifreeze should be mixed 
              to make 4 liters of the 40% antifreeze.


Solution

Let x be the volume of the pure antifreeze.

Then the volume of the 40% antifreeze should be  (4-x) liters.


The basic equation is

    x + 0.4*(4-x) = 0.7*4

saying that the sum of antifreeze volumes in ingredients is equal to the volume of the antifreeze in the mixture.


From equation, express x and calculate


    x = %280.7%2A4+-+0.4%2A4%29%2F%281-0.4%29 = 2 liters.


ANSWER.  2 liters of the 70% antifreeze should be mixed with 2 liters of the pure antifreeze.

Solved.

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There is a bunch of introductory lessons in this site,  covering various types of mixture problems
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Word problems on mixtures for antifreeze solutions
    - Word problems on mixtures for alloys
    - Typical word problems on mixtures from the archive

Read them and become an expert in solution the mixture word problems.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Mixture problems".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.