SOLUTION: Hi eight times the sum of the digits of a two digit number exceeds the number by 19. The tens digit is 3 more than the units digit. What is the number. Thanks

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Question 1147686: Hi
eight times the sum of the digits of a two digit number exceeds the number by 19. The tens digit is 3 more than the units digit. What is the number.
Thanks
Answer by Edwin McCravy(20065) About Me  (Show Source):
You can put this solution on YOUR website!
u = units or ones digit
t = tens digit
10t+u = the number
eight times the sum of the digits of a two digit number 
8∙(t + u)
exceeds the number by 19.
8∙(t + u) = (10t + u) + 19
  8t + 8u = 10t + u + 19
 -2t + 7u = 19

The tens digit is 3 more than the units digit. 
t = u + 3

What Is the number.
We have this system of two equations and two unknowns:

system%28-2t%2B7u+=+19%2Ct=u%2B3%29

You finish.  Solve that by substitution

Edwin