SOLUTION: The count in a bacteria culture was 200 after 15 minutes and 2000 after 40 minutes. Assuming the count grows exponentially, what is the doubling period?

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Question 1147675: The count in a bacteria culture was 200 after 15 minutes and 2000 after 40 minutes. Assuming the count grows exponentially,
what is the doubling period?

Found 2 solutions by josmiceli, ikleyn:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+P+=+P%280%29%2A%28+1+%2B+r+%29%5Et+
+200+=+P%280%29%2A%28+1+%2B+r+%29%5E15+
+200%2FP%280%29+=+%28+1+%2B+r+%29%5E15+
and
+2000+=+P%280%29%2A%28+1+%2B+r+%29%5E40+
+2000%2FP%280%29+=+%28+1+%2B+r+%29%5E40+
+200%2FP%280%29+=+%281%2F10%29%2A%28+1+%2B+r+%29%5E40+
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+%28+1+%2B+r+%29%5E15+=+%281%2F10%29%2A%28+1+%2B+r+%29%5E40+
divide both sides by +%28+1+%2B+r+%29%5E15+
+1+=+%281%2F10%29%2A%28+1+%2B+r+%29%5E25+
+10+=+%28+1+%2B+r+%29%5E25+
Take the log base 10 of both sides
+1+=+25%2Alog%28+1+%2B+r+%29+
+log%28+1+%2B+r+%29+=+.04+
+1+%2B+r+=+10%5E.04+ ( I'll refer back to this step )
+1+%2B+r+=+1.09648+
+r+=+.09648+
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To find doubling period:
+2P%280%29+=+P%280%29%2A%28+1+%2B+r+%29%5Et+
+2+=+%28+1+%2B+r+%29%5Et+
Take log base 10 of both sides
+log%282%29+=+t%2Alog%28+10%5E.04+%29+ ( from the above mentioned step )
+.30103+=+t%2A.04+
+t+=+7.526+
The doubling period is 7.526 min
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Get another opinion if needed

Answer by ikleyn(52890) About Me  (Show Source):
You can put this solution on YOUR website!
.

The shortest way to solve the problem is THIS:


    2000%2F200 = 2%5Et


    10 = 2%5Et.


Take logarithm base 2 of both sides.


    log%282%2C%2810%29%29 = t


Find  log%282%2C%2810%29%29  by any way you can.  // I use my MS Excel in my computer, as always.


    t = 3.32.


Thus 40-15 = 25 minutes  is 3.32 times the doubling period.


Hence, the doubling period is   25%2F3.32 = 7.5 minutes (approximately).    ANSWER

Solved.