SOLUTION: If Drink A contains 22% water and Drink B contains 97% water. How much of each solution should be mixed in order to create 25 milliliters of a solution that contains 82% water?
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Question 1147563: If Drink A contains 22% water and Drink B contains 97% water. How much of each solution should be mixed in order to create 25 milliliters of a solution that contains 82% water? Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39623) (Show Source):
The formula which @josgarithmetic presents as a final answer, is INCORRECT,
So I came to present the correct solution.
x of 97%
25-x of 22%
0.97*x + 0.22*(25-x) = 0.92*25
0.97x + 0.22*25 - 0.22x = 92*25
(0.97-0.22)x = 0.92*25 - 0.22*25
x = = 23.333.
ANSWER. 23.333 mL of the drink B and (25-23.333) = 1.666 mL of the drink A.
CHECK. = 0.92, which is CORRECT concentration value.
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