SOLUTION: An airplane is flying at 340 mph with a heading of 210 degrees. If a 50 mph wind is blowing from the west, find the actual ground speed and course of the airplane.

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Question 114732: An airplane is flying at 340 mph with a heading of 210 degrees. If a 50 mph wind is blowing from the west, find the actual ground speed and course of the airplane.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Assuming east is positive x, north is positive y, break down the airplane's velocity into a vector in the x-y plane.
The plane is traveling 340 mph at a bearing of 210 degrees or (340cos(210), 340 sin(210)).
The wind is blowing from the west (to the east) at 50 mph or (50,0).
The actual ground speed would be the vector sum of those two (340 cos(210)+50, 340 sin(210)) or (-294.4+50,-170) or (-244.4,-170).
The magnitude of that velocity vector is
V%5E2=244.4%5E2%2B170%5E2
V%5E2=88655
V=297.8
For direction
tan%28alpha%29+=+170%2F244.4
tan%28alpha%29+=+0.6956
%28alpha%29+=+34.8
Since this angle is measured from the (-y) axis, we add 180 to get the actual heading.
The plane is traveling at 297.8 mph at a heading of 214.8 degrees.