SOLUTION: The length of a new rectangular playing field is 2 yards longer than quadruple the width. If the perimeter of the rectangular playing field is 454 yards, what are its dimens
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Question 1147284: The length of a new rectangular playing field is 2 yards longer than quadruple the width. If the perimeter of the rectangular playing field is 454 yards, what are its dimensions? Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website! let l be the length of the rectangular playing field and w be its width, then
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l = 4w +2
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Perimeter = 2l +2w
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2(4w +2) + 2w = 454
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8w +4 +2w = 454
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10w = 450
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w = 45
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l = 4(45) +2 = 182
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The dimensions of the rectangular playing field are length 182 yards and width is 45 yards
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check the answer
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2(182) +2(45) = 454
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364 + 90 = 454
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454 = 454
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answer checks
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