SOLUTION: Distribution with a mean of 123 and standard deviation of 8 is transformed into a standardized distribution with a mean of 54 and standard deviation of 5. Find the new standardized
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Question 1147128: Distribution with a mean of 123 and standard deviation of 8 is transformed into a standardized distribution with a mean of 54 and standard deviation of 5. Find the new standardized score when the original value is X=130
My solution:
130-123/8 = 0.875
In the standardized distribution: 5*0.875=4.375
So new score is 54 + 4.375= 58. 375 ? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! Yes, that's how you do it.
The z score for the value of 130 in the original distribution is 7/8
Therefore, that has to be the z-score of the new value in the second distribution.
Since the z-score is (x-mean)/sd you get the result you got.
