SOLUTION: Write the equation of tangent to 3x^2+4y^2-2x+6y-25=0 at line 2y-8x=0

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Question 1147041: Write the equation of tangent to
3x^2+4y^2-2x+6y-25=0 at line 2y-8x=0
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Write the equation of tangent to
3x^2+4y^2-2x+6y-25=0 at line 2y-8x=0
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"at line 2y-8x=0" makes no sense
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3x^2+4y^2-2x+6y-25=0
Differentiate implicitly.
6x*dx + 8y*dy - 2dx + 6dy = 0
(6x-2)dx = (-8y-6)dy
dy/dx = -(3x-1)/(4y+3) = slope of the tangent line at any point on the ellipse