SOLUTION: Find a polynomial f(x) of degree 3 that has the indicated zeros and satisfies the given condition. −3, −2, 0; f(−4) = 16

Algebra ->  College  -> Linear Algebra -> SOLUTION: Find a polynomial f(x) of degree 3 that has the indicated zeros and satisfies the given condition. −3, −2, 0; f(−4) = 16      Log On


   

Question 1146984: Find a polynomial f(x) of degree 3 that has the indicated zeros and satisfies the given condition.
−3, −2, 0; f(−4) = 16
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


f%28x%29+=+a%28x%2B3%29%28x%2B2%29%28x%29

f%28-4%29+=+a%28-1%29%28-2%29%28-4%29+=+-8a+=+16
a+=+-2

ANSWER: f%28x%29+=+-2%28x%2B3%29%28x%2B2%29%28x%29

Expand if required....

A graph....

graph%28400%2C400%2C-5%2C5%2C-20%2C20%2C-2%28x%2B3%29%28x%2B2%29%28x%29%29