| 
 
 
| Question 1146943:  The horizontal line y = k intersects the parabola with equation y = 2(x-3)(x-5) at points A and B. If the length of line segment AB is 6, what is th value of k?
 Found 3 solutions by  Alan3354, ikleyn, greenestamps:
 Answer by Alan3354(69443)
      (Show Source): 
You can put this solution on YOUR website! The horizontal line y = k intersects the parabola with equation y = 2(x-3)(x-5) at points A and B. If the length of line segment AB is 6, what is th value of k? ------------------
 y = 2(x-3)(x-5) = 2x^2 -16x + 30
 ---
 The zeroes are 3 & 5, and the vertex is (4,-2)
 --
 Find the equation of the "similar" parabola with vertex (0,-2)
 Its zeroes are -1 & +1.
 ----
 y = ax^2 + bx + c
 --
 At (-1,0): 0 = a - b + c
 At (1,0): 0 = a + b + c
 ----------------------------- Subtract
 b = 0
 ===========
 At (0,-2): -2 = c
 --> y = 2x^2 - 2
 -------------------
 Find y where x = -3 or +3
 y = 2*9 - 2 = 16
 ---> k = 16
 ================================
 Might be a "better" or shorter way, but k = 16 regardless.
 
 
 
Answer by ikleyn(52879)
      (Show Source): 
You can put this solution on YOUR website! . 
 
The equation
    2*(x-3)*(x-5) = k
is equivalent to
    2x^2 - 16x + 30 = k,   or
    2x^2 - 16x + (30-k) = 0,  or
     x^2 - 8x +  = 0.
According to Vieta's theorem, the sum of the roots is equal to coefficient at "x" with the opposite sign, i.e. 8.
The difference of the roots is equal to 6 (given).
If "a" is the greater root, then the other root is (8-a), and the difference between them is
    6 = a - (8-a) = 2a - 8,
which implies  
    2a = 6 + 8 = 14,
     a = 7.
Thus the greater root is  a= 7, while the smaller root is  8-a = 8-7 = 1.
The product of the roots, 7*1, is equal to the constant term  , according to Vieta's theorem (again (!) ).
Thus you have this equation for k  = 7,
which implies
    30 - k = 14.
Hence,  k = 30-14 = 16.Solved.
 
 VERY GOOD problem on Vieta's theorem (!)
 
 
 
Answer by greenestamps(13209)
      (Show Source): 
You can put this solution on YOUR website! 
 The parabola has zeros at x=3 and x=5, so the axis of symmetry is x=4.
 
 For the length of AB to be 6, the x values of points A and B have to be 3 either side of the axis of symmetry; so the x values of points A and B are 1 and 7.
 
 Substitute either x=1 or x=7 into the equation to find the y value at those points, which is the value of k the question asks for.
 
 
  
 ANSWER: k = 16
 | 
  
 | 
 |