Question 1146804: Bob has 40 cents in his pocket. If bob has no pennies, how many different coin combinations of quarters, dimes and/or nickels could bob have
Found 2 solutions by VFBundy, greenestamps:
Answer by VFBundy(438)   (Show Source):
You can put this solution on YOUR website! 1) 1 quarter, 1 dime, 1 nickel
2) 1 quarter, 3 nickels
3) 4 dimes
4) 3 dimes, 2 nickels
5) 2 dimes, 4 nickels
6) 1 dime, 6 nickels
7) 8 nickels
Answer by greenestamps(13198)  (Show Source):
You can put this solution on YOUR website!
Clearly he can only have either 1 quarter or none.
(1) If he has a quarter, that is 25 of the 40 cents; 15 cents remain. He can have either 1 dime or no dimes; nickels will make up the rest.
2 solutions with 1 quarter.
(2) If he has no quarters, then the number of dimes he can have is any number from 0 to 4; again nickels will make up the rest.
5 solutions with no quarters.
Total number of combinations: 2+5 = 7
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