SOLUTION: Please help me answer this question. "A family drove 45 km then hiked 1 km to their campsite. The trip took 1 hour and 15 min. If they drove 55 km/h faster than they hiked, how fas

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Please help me answer this question. "A family drove 45 km then hiked 1 km to their campsite. The trip took 1 hour and 15 min. If they drove 55 km/h faster than they hiked, how fas      Log On

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Question 1146769: Please help me answer this question. "A family drove 45 km then hiked 1 km to their campsite. The trip took 1 hour and 15 min. If they drove 55 km/h faster than they hiked, how fast did they drive?"
Answer by ikleyn(52898) About Me  (Show Source):
You can put this solution on YOUR website!
.
Let u be their rate driving (the value under the question).


Then their rate hiking is (u-55) kilometers per hour, according to the condition.


Time to driving 45 km  was  45%2Fu hours.


Time for hiking 1 kilometer was  1%2F%28u-55%29 hours.


The total time was 1 hour 15 minutes = 5%2F4 hours.


So, the "time" equation is


    45%2Fu + 1%2F%28u-55%29 = 5%2F4   hours.


It is your basic equation.


To solve it, multiply both sides by 4u*(u-55), then reduce the obtained quadratic equation to its standard form.


Solve it using the quadratic formula or factoring - whichever method does work.

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