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Question 1146601: Find the distance from point A(15,−21) to the line 5x+2y = 4. Round your answer to the nearest tenth.
Found 2 solutions by MathLover1, greenestamps: Answer by MathLover1(20850) (Show Source):
You can put this solution on YOUR website!
Find the distance from point to the given line
A( , ),
.....first, write in slope intercept form
The slope of your GIVEN line is .
The slope of the line you want to find (perpendicular line) must have slope inverse reciprocal which is .
Line you want:
, using point-slope form
WHY? The two lines intersect at some point which you will find.
Then use Distance formula to find the length from the intersection point to point A( , ).
You are first looking for the line perpendicular to the given one which contains point .
Now find intersection point of and . So, all you need is equal right sides.
go to , plug in and solve for
intersection point is at ( , )
now use Distance formula to find the length from the intersection point to point A
A( , ) = ( , )
( , ) = ( , )
=> exact solution
=>to the nearest tenth
Answer by greenestamps(13216) (Show Source):
You can put this solution on YOUR website!
The response from the other tutor shows a detailed solution to the problem.
You should be able to understand all the steps required for the solution; and you should be able to solve a similar problem by that method.
However, in practice, there is a concise formula for finding the (shortest) distance from a given point to a given line. When the equation of the line is in the form Ax+By+C=0, then the distance from a point (p,q) to the line is

In the required form, the equation in this problem is 5x+2y-4 = 0. Then the distance from (15,-21) to that line is
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