SOLUTION: This system of equations relates the ticket price, in dollars, for seats in the silver (x) and gold (y) sections at a rock concert.
x + 2y = 82
3x + y = 96
By how much does
Question 1146501: This system of equations relates the ticket price, in dollars, for seats in the silver (x) and gold (y) sections at a rock concert.
x + 2y = 82
3x + y = 96
By how much does the price of a ticket for the gold section exceed the price for a ticket for the silver section? Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website! x is the price of tickets in the silver section.
y is the price of tickets in the gold section.
multiply the first equation by 3 and leave the second equation as is to get:
3x + 6y = 246
3x + y = 96
subtract the second equation from the first to get:
5y = 150
solve for y to get y = 30
since x + 2y = 82 and y = 30, you get x + 60 = 82
solve for x to get x = 22
you have x = 22 and y = 30
replace x with 22 and y with 30 in both original equations to get:
x + 2y = 82 becomes 22 + 60 = 82 which becomes 82 = 82
3x + y = 96 becomes 66 + 30 = 96 which becomes 96 = 96
both original equations are true which confirms the values for x and y are good.
your solution is that the price of a gold ticket exceeds the price of a silver ticket by 8 (30 -22 = 8).
