SOLUTION: snack mix A is 12% sodium and snack mix B is 4% sodium. we want to make a 40oz snack mix that is 9% sodium. how much of each snack mix is needed?

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Question 1146493: snack mix A is 12% sodium and snack mix B is 4% sodium. we want to make a 40oz snack mix that is 9% sodium. how much of each snack mix is needed?
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39623) About Me  (Show Source):
You can put this solution on YOUR website!
The example application is very bad!


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mix A is 12% target material and mix B is 4% target material. we want to make a 40 ounce mix that is 9% target material. how much of each A and B mix is needed?
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v, amount of the 12% material
M, amount of finished mixture
M=40
T=9
H=12
L=4

Hv%2BL%28M-v%29=TM------solve for v.
-
Hv%2BLM-Lv=TM
%28H-L%29v%2BLM=TM
%28H-L%29v=TM-LM
v=%28TM-LM%29%2F%28H-L%29
highlight%28v=M%28%28T-L%29%2F%28H-L%29%29%29

Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!


There are many ways to solve "mixture" problems like this, including using the ugly formula that the other tutor showed.

But here is what is surely the fastest and easiest way....

(1) The 9% target percentage is 5/8 of the way from 4% to 12%, the percentages of the two ingredients.
(2) That means 5/8 of the mixture is the higher percentage ingredient.

ANSWER: 5/8 of 40 ounces, or 25 ounces, of the 12% sodium snack mix A; the other 15 ounces of snack mix B.