SOLUTION: A standard deck of cards contains 52 cards. One card is selected from the deck. Compute probability.
A) P(Nine or four)
B) P(nine or four or six)
c) P (quee
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-> SOLUTION: A standard deck of cards contains 52 cards. One card is selected from the deck. Compute probability.
A) P(Nine or four)
B) P(nine or four or six)
c) P (quee
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Question 1146440: A standard deck of cards contains 52 cards. One card is selected from the deck. Compute probability.
A) P(Nine or four)
B) P(nine or four or six)
c) P (queen or diamond) Found 2 solutions by Glaviolette, Alan3354:Answer by Glaviolette(140) (Show Source):
You can put this solution on YOUR website! A. Since there are 4 nines and 4 fours, the P(Nine or four) = 4/52 + 4/52 = 8/52 = 2/13
B. P(nine or four or six) adds 4 more to be 12/52 = 3 /13
C. There are 4 queens and 13 diamonds. However, there's a queen that is alsa diamond. P(queen or diamond) = 4/52 + 13/52 - 1/52 = 16/52 = 4/13
You can put this solution on YOUR website! A standard deck of cards contains 52 cards. One card is selected from the deck. Compute probability.
A) P(Nine or four)
Four 9's + four 4's
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8/52
B) P(nine or four or six)
12/52
c) P (queen or diamond)
Four Q's + 12 other diamonds (the Q is already counted)
(4+12)/52
