Question 1146315: The sum of the ages of Kevin and Rebecca is 54 years. 6 years ago, Kevin's age was 2 times Rebecca's age. How old is Kevin now? Found 2 solutions by ankor@dixie-net.com, MathTherapy:Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! let k + K's present age
let r + R's age
:
write an equation for each statement
:
The sum of the ages of Kevin and Rebecca is 54 years.
k + r = 54
6 years ago, Kevin's age was 2 times Rebecca's age.
k - 6 = 2(r - 6)
k - 6 = 2r - 12
k = 2r - 12 + 6
k = 2r - 6
Rearrange and subtract from the 1st equation
k - 2r = -6
:
k + r = 54
k -2r = -6
---------------Subtraction eliminates k, find r
0 + 3r = 60
r = 60/3
r = 20 yr is Rebeccas'age
and
54 - 20 = 34 yrs is Kevin's age
:
:
Check this in the statement
"6 years ago, Kevin's age was 2 times Rebecca's age."
34 - 6 = 2(20-6)
28 = 2(14)
You can put this solution on YOUR website!
The sum of the ages of Kevin and Rebecca is 54 years. 6 years ago, Kevin's age was 2 times Rebecca's age. How old is Kevin now?
Let Kevin's age be K
Then Rebecca's is 54 - K
We then get: K - 6 = 2(54 - K - 6)
K - 6 = 2(48 - K)
K - 6 = 96 - 2K
3K = 102
K, or Kevin is:
