SOLUTION: Evaluate the discriminant b^2-4ac. Then use the answer to state how many real-number solutions exist for the equation. y=x^2+8x+16

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Question 114623This question is from textbook
: Evaluate the discriminant b^2-4ac. Then use the answer to state how many real-number solutions exist for the equation. y=x^2+8x+16
 This question is from textbook

Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
a=1, b=8, c=16
b^2-4ac=64-4*1*16
=64-64=0
There is only one real number solution.
If the discriminent was negative there would be none and if it was positive there would be two.
x^2+8x+16=0
(x+4)(x+4)=0
x=-4
Ed
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