SOLUTION: Y is the midpoint of line XZ. If line YZ=2x+8 and XZ=6x-26, find the value of XY. I don't understand. Someone plz explain.

Algebra ->  Length-and-distance -> SOLUTION: Y is the midpoint of line XZ. If line YZ=2x+8 and XZ=6x-26, find the value of XY. I don't understand. Someone plz explain.      Log On


   

Question 1146225: Y is the midpoint of line XZ. If line YZ=2x+8 and XZ=6x-26, find the value of XY. I don't understand. Someone plz explain.
Found 2 solutions by math_helper, josgarithmetic:
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!


You have    X----------Y----------Z



            |          |<- 2x+8 ->|

            |                     |

            |<-----  6x-26 ------>|





XY  = (6x-26) - (2x+8)  AND  we know  XY = YZ b/c Y is the midpoint of XZ, so  





           (6x-26) - (2x+8) = (2x+8)

     

Solving for x:   x = 21   -->   XY = 2(21)+8 = 50



+XY+=+highlight%2850+%29



Check:



XY = 50 

YZ = 50

XZ = 50+50 = 100 by adding the two segment lengths and by the

formula: 6x-26, XZ=6(21)-26 = 126-26 = 100    



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Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Y is the midpoint of cross%28line%29 SEGMENT XZ. If cross%28line%29 SEGMENT LENGTH YZ = 2x+8 and SEGMENT LENGTH XZ = 6x-26, find the value of XY.