SOLUTION: When a child emptied her coin bank, she had a collection of pennies, nickels, and dimes. There were a total of 50 pennies, and a combined total of 30 nickels and dimes. If the coin
Algebra ->
Customizable Word Problem Solvers
-> Coins
-> SOLUTION: When a child emptied her coin bank, she had a collection of pennies, nickels, and dimes. There were a total of 50 pennies, and a combined total of 30 nickels and dimes. If the coin
Log On
Question 1146173: When a child emptied her coin bank, she had a collection of pennies, nickels, and dimes. There were a total of 50 pennies, and a combined total of 30 nickels and dimes. If the coins had a total value of 250 cents, how many nickels and dimes were in the bank?
The starting point is to immediately subtract the 50 pennies to arrive at 200 cents worth of nickels and dimes.
N = number of nickels
30-N = number of dimes
5N + 10(30-N) = 200
-5N + 300 = 200
5N = 100
N = 20 nickels --> and (30-20) = 10 dimes
---
Check: 5*20 + 10*10 = 100 + 100 = 200 cents (that plus the original 50 pennies gets you to 250 cents in the coin bank).
----
Some tutors will show you other ways to solve it. Those are probably fine methods, I just prefer the mechanical method above.