SOLUTION: An 18kg mass is placed at one end of a steel bar that is 1m long. A 35kg mass is placed at the other end. Where should the fulcrum be placed to balance the bar? If anyone can

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Question 114613This question is from textbook Algebra Structure and Method
: An 18kg mass is placed at one end of a steel bar that is 1m long. A 35kg mass is placed at the other end. Where should the fulcrum be placed to balance the bar?
If anyone can help me solve this problem I would appreciate it!!!
Please and Thank You!!! This question is from textbook Algebra Structure and Method

Found 2 solutions by checkley71, scott8148:
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
35X=18(1-X)
35X=18-18X
35X+18X=18
53X=18
X=18/53
.34 METERS FROM THE 35 KG MASS IS THE FULCRUM.
PROOF
.35*.34=18(1-.34)
.119=18*.66
.119=.119

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
for the bar to balance; the products of the masses and their distances from the fulcrum must be equal
___ (m1)(d1)=(m2)(d2)

let x="35 kg distance", so 1-x="18 kg diatance"

35x=18(1-x) ___ 35x=18-18x ___ 53x=18