SOLUTION: Find two consecutive integers such that the sum of 2 times the first integer and 7 times second integer is 88.
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Question 114606: Find two consecutive integers such that the sum of 2 times the first integer and 7 times second integer is 88. Answer by jgr45(31) (Show Source):
You can put this solution on YOUR website! x = first integer
x+1 = second integer
sum of 2 times the first integer and 7 times second integer
2x + 7(x+1) = 88
2x + 7x + 7 = 88
9x + 7 = 88
9x = 81
x = 9
Integers are 9 and 10.
Check: 2(9)+7(10) =? 88
18 + 70 =? 88
88 = 88 √
