SOLUTION: According to a report, 9.5% of all full-time S.A. undergraduate students study abroad. Assume that 60% of the undergraduate students who study abroad are female and that 49% of the
Algebra ->
Probability-and-statistics
-> SOLUTION: According to a report, 9.5% of all full-time S.A. undergraduate students study abroad. Assume that 60% of the undergraduate students who study abroad are female and that 49% of the
Log On
Question 1145848: According to a report, 9.5% of all full-time S.A. undergraduate students study abroad. Assume that 60% of the undergraduate students who study abroad are female and that 49% of the undergraduate students who do not study abroad are female. A full-time S.A. undergraduate student is randomly selected.
2.1) What is the probability that the student is female and studying abroad (rounded off to three decimals)? [2]
2.2) What is the probability that the student is female and not studying abroad (rounded off to three decimals)? [2]
2.3) What is the probability that the student is female (rounded off to four decimals)? [3]
2.4) What is the probability that the student is male (rounded off to four decimals)? [1]
2.5) What is the overall percentage of full-time female students and male students (rounded off to zero decimals)?
You can put this solution on YOUR website! % of full-time S.A. undergraduate students who study abroad = 0.095
% of full-time S.A. undergraduate students who do not study abroad = 0.905
% of undergraduate students who study abroad that are female = 0.60
% of undergraduate students who study abroad that are male = 0.40
% of undergraduate students who not do study abroad that are female = 0.49
% of undergraduate students who not do study abroad that are male = 0.51 2.1) What is the probability that the student is female and studying abroad (rounded off to three decimals)?
0.60 * 0.095 = 0.057 2.2) What is the probability that the student is female and not studying abroad (rounded off to three decimals)?
0.49 * 0.905 = 0.443 2.3) What is the probability that the student is female (rounded off to four decimals)?
(0.60 * 0.095) + (0.49 * 0.905) = 0.057 + 0.443 = 0.500 2.4) What is the probability that the student is male (rounded off to four decimals)?
(0.40 * 0.095) + (0.51 * 0.905) = 0.038 + 0.462 = 0.500
Or...you could have simply subtracted the result from Question 2.3 from 1. 2.5) What is the overall percentage of full-time female students and male students (rounded off to zero decimals)
From last two questions...50/50.
