SOLUTION: How many ounces of hard candy at 20 cents per ounce must be mixed with 20 ounces of chocolate at 40 cents per ounce to get a total mixture to sell at 35 cents per ounce
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: How many ounces of hard candy at 20 cents per ounce must be mixed with 20 ounces of chocolate at 40 cents per ounce to get a total mixture to sell at 35 cents per ounce
Log On
Question 1145787: How many ounces of hard candy at 20 cents per ounce must be mixed with 20 ounces of chocolate at 40 cents per ounce to get a total mixture to sell at 35 cents per ounce Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Same problem, different numbers and substances.
=================
How many mililiters of a 30 percent solution must be mixed with 12 mililiters of a 5 percent solution to obtain a 20 percent solution
-----------
Add M mls of 30%
---
M*30 + 12*5 = (M + 12)*20
