SOLUTION: At a community yard sale, all items were priced at either $2 or $5. A total of 150 items were sold for a total of $405. This situation is modeled by the system of equations shown

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: At a community yard sale, all items were priced at either $2 or $5. A total of 150 items were sold for a total of $405. This situation is modeled by the system of equations shown       Log On


   

Question 1145765: At a community yard sale, all items were priced at either $2 or $5. A total of 150 items were sold for a total of $405. This situation is modeled by the system of equations shown below, where x represents the number of $2 tem and y represents the number of $5 items. x + y = 150 2x + 5y = 405 Bed on the system of equations, what was the total number of $5 tems sold at the yard sale?
Answer by ikleyn(52788) About Me  (Show Source):
You can put this solution on YOUR website!
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From the first equation, express x = 150 - y  and substitute it into the second equation. 

You will get the equation for "y", the number of $5 items


    2*(150-y) + 5y = 405   dollars.


From this equation, express "y" and calculate


    y = %28405-2%2A150%29%2F%285-2%29 = 35.


ANSWER.  35 of the $5 items were sold.