SOLUTION: Betty and Chris have a system of walking and jogging equal distances through a course in their neighbourhood. They walk at a rate of 6km/h and jog at a rate of 12km/h The total tim
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-> SOLUTION: Betty and Chris have a system of walking and jogging equal distances through a course in their neighbourhood. They walk at a rate of 6km/h and jog at a rate of 12km/h The total tim
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Question 1145633: Betty and Chris have a system of walking and jogging equal distances through a course in their neighbourhood. They walk at a rate of 6km/h and jog at a rate of 12km/h The total time required for them to walk and jog through the course is 2h How long is the course? Answer by ikleyn(52794) (Show Source):
Let "d" be the walking distance, in kilometers (the same as jogging distance (!) ).
Then the time walking is hours, while the time jogging is hours.
Total time is 2 hours
+ = 2 hours.
It is your basic equation. (Also called "time" equation)
At this point, the setup is completed.
To solve the equation, multiply both sides by 12
2d + d = 2*12
3d = 24
d = 24/3 = 8 kilometers.
Distance walking = distance jogging = 8 kilometers.
The course is 8 + 8 = 16 kilometers long. ANSWER
Solved.
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Using "time" equation is the STANDARD method of solving such problems.
From my post, learn on how to write, how to use and how to solve a "time" equation.
