SOLUTION: Tania is planning to buy a cage for her pet Miracle-a puppy. She wants that the length of the cage is 10 more than the height. The width is twenty less than twice the height and th

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Tania is planning to buy a cage for her pet Miracle-a puppy. She wants that the length of the cage is 10 more than the height. The width is twenty less than twice the height and th      Log On

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Question 1145520: Tania is planning to buy a cage for her pet Miracle-a puppy. She wants that the length of the cage is 10 more than the height. The width is twenty less than twice the height and the height measures 25 inches. Find the volume of the cage (in cubic feet) to make sure that there is enough space for Miracle to move around.
Answer by thmei1(4) About Me  (Show Source):
You can put this solution on YOUR website!
Let length of cage = l
Let width = w
Let height = h
volume= B*h= (length*width)*height
length is 10 more than the height = h + 10
width is twenty less than twice the height = (2*h) - 20
height = 25 inches
substitute 25 for height
length= h+10= 25+10= 35 inches
width= 2h-20= 2(25)-20= 50-20= 30 inches
volume= B*h= (length*width)*height
volume= B*h= (35 inches*30 inches)*25 inches
12 inches per 1 feet, want units in feet not inches
volume= B*h= (2.92 ft*2.5 ft)*2.08 ft = 15.2 cubic feet
Volume = 15.2 cubic feet (or 15.2 ft^3)