Question 1145464: the equation of a line that passes through the point (-2,6) and is parallel to the line that passes through the points (0, -4) and (3, 2).
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! the equation of a line that passes through the point (-2,6) and is parallel to the line that passes through the points (0, -4) and (3, 2).
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Step 1, find the slope of the line.
Slope m = diffy/diffx
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Step 2: all parallel lines have the same slope.
Use
y-y1 = m*(x-x1)
where (x1,y1) is the given point (-2,6)
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