SOLUTION: Find three consecutive even integers where the sum of triple the first and twice the second is eight more than four times the third. ____x+___(____)=8(____)______ 1x+3(x-2)=8(x

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Find three consecutive even integers where the sum of triple the first and twice the second is eight more than four times the third. ____x+___(____)=8(____)______ 1x+3(x-2)=8(x      Log On


   



Question 1145413: Find three consecutive even integers where the sum of triple the first and twice the second is eight more than four times the third.
____x+___(____)=8(____)______
1x+3(x-2)=8(x-4)-3
is what I have I don't think the equation is correct

Answer by josgarithmetic(39631) About Me  (Show Source):
You can put this solution on YOUR website!
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the sum of triple the first and twice the second is eight more than four times the third.
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first, x
second, x+2
third, x+4

3x%2B2%28x%2B2%29=4%28x%2B4%29%2B8
.
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