SOLUTION: The product of two consecutive integers is 5 less than the square of the lesser integer. Find the greater of the two integers.
Algebra ->
Average
-> SOLUTION: The product of two consecutive integers is 5 less than the square of the lesser integer. Find the greater of the two integers.
Log On
Question 1145373: The product of two consecutive integers is 5 less than the square of the lesser integer. Find the greater of the two integers. Found 2 solutions by richwmiller, ikleyn:Answer by richwmiller(17219) (Show Source):
x*(x+1) = x^2 - 5
x^2 + x = x^2 - 5
x = -5 is the lesser number.
x = -4 is your ANSWER.
CHECK. a) (-5)*(-4) = 20. b) (-5)*(-5) - 5 = 25 - 5 = 20.
! Correct !
