SOLUTION: Hi I need help on this word problem. Susan invests 2 times as much money at 10% as she does at 6%. If her total interest after 1 year is $780, how much does she have invested a

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: Hi I need help on this word problem. Susan invests 2 times as much money at 10% as she does at 6%. If her total interest after 1 year is $780, how much does she have invested a      Log On

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Question 1145187: Hi I need help on this word problem.
Susan invests 2 times as much money at 10% as she does at 6%. If her total interest after 1 year is $780, how much does she have invested at each rate?

Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52775) About Me  (Show Source):
You can put this solution on YOUR website!
.

Hey,

an educated person would ask "Could you PLEASE help me . . . ".



Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
x at 6%
2x at 10%

If assume simple interest rates, for $780 interest after a year,
0.06x%2B0.1%2A2x=780
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