SOLUTION: A pawnbroker buys a computer and a guitar for $500. He sells the computer at a markup of 40% but has to take a loss of 10% on the guitar in order to sell it if he makes a profit of

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: A pawnbroker buys a computer and a guitar for $500. He sells the computer at a markup of 40% but has to take a loss of 10% on the guitar in order to sell it if he makes a profit of      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1144879: A pawnbroker buys a computer and a guitar for $500. He sells the computer at a markup of 40% but has to take a loss of 10% on the guitar in order to sell it if he makes a profit of $110 on the sale of the two items what did he pay for the computer
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
He sold the computer at 140% (profit of 40%, add to 100%) of what he paid but
he sold the guitar for only 90% (loss of 10%, subtract from 100%) of what he
paid. Let C and G stand fot the costs.  Change the percents to decimals. He
sold them both for $500+$110 or $610.

system%28C%2BG=500%2C1.40C%2B0.90G=610%29

Clear the decimals, solve by substitution or elimination. You finish.

Edwin