Question 1144784: What amount of a 15% HCL acid solution must be mixed with a 20% HCL acid solution to obtain 50 milliliters of 18% solution? Answer by ikleyn(52787) (Show Source):
Let x be the amount of the 15% solution, in milliliters.
Then the amount of the 20% solution is 50-x milliliters.
The equation to find "x" is this
0.15x + 0.20*(50-x) = 0.18*50.
It says that the amount of the pure acid HCl in the mixture is the sum of the amounts of the pure acid HCl in the ingredients.
Express x from the equation and calculate
x = = 20 milliliters. ANSWER
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