One bus travels 12 km/h slower than the other...
Let the faster bus's speed be r km/h.
Then the slower bus's speed is r-12 km/h.
...travel toward each other.
Since they travel toward each other, their speed of approach is the sum
of their speeds, r + r-12 which is 2r-12 km/h
...they meet in 3 hours,...
That means the distance between them goes from 732 km to 0 km in 3 hours.
...what is the rate of each bus?
Distance = (rate)(time)
732 = (2r-12)(3)
Divide both sides by 3
244 = 2r-12
Add 12 to both sides
256 = 2r
Divide both sides by 2
128 = r
So the faster bus went 128 km/h
The slower bus went 128-12 or 116 km/h
That's really fast! So let's check how far each
went in 3 hours.
The faster bus went 128 km/h for 3 hours and therefore went (128)(3)=384 km.
The slower bus went 116 km/h for 3 hours and therefore went (116)(3)=348 km.
So their distances traveled until they met should add up to 732 km.
And they do!:
384 km + 348 km = 732 km.
So the answers 128 and 116 km/h are correct. Hope they didn't get a ticket! lol
Edwin
